Is #f(x)=(x+3)(x-6)(x/3-1)# increasing or decreasing at #x=-2#?
1 Answer
Mar 15, 2018
Explanation:
#"To determine if "f(x)" is increasing/decreasing at"#
#"x = -2 differentiate and evaluate at x = - 2"#
#• " if "f'(-2)>0" then "f(x)" is increasing at x = - 2"#
#• " if "f'(-2)<0" then "f(x)" is decreasing at x = - 2"#
#"expanding the factors gives"#
#f(x)=1/3x^3-2x^2-3x+18#
#rArrf'(x)=x^2-4x-3#
#rArrf'(-2)=4+8-3=9>0#
#"Since "f'(-2)>0" then "f(x)" is increasing at x = - 2"#
graph{(x+3)(x-6)(1/3x-1) [-20, 20, -10, 10]}