Question

Is the equation `St=u+1/2 a*(2t-1)` dimensionally correct? I mean Dimension of S and U are not the same,right?

Answer 1

Well,firstly I must praise you for your observation,you have nicely detected a problem.

Well,looking into how the eqution was derived,you will get that,

It tells us about displacement in unit second,as we calculate by subtracting displacement occured in `(t+1)` th `s` - displacement occured in `t` th `s`

So,apparently,the displacement we calculate from the equation is displacement occured in `1s` which corresponds to velocity,

So,basically `S_t` is `(S_t)/(1s)`

so it has the dimension of `[LT^-1]`