# Is the function f(x) = (x^2+8)^2 even, odd or neither?

We show that $f \left(- x\right) = f \left(x\right)$ hence we have
$f \left(- x\right) = {\left({\left(- x\right)}^{2} + 8\right)}^{2} = {\left({x}^{2} + 8\right)}^{2} = f \left(x\right)$