Is this correct?

Question

#r=5-4sin(pi-theta)#

#r=5-4sinpicostheta-cospisintheta#

#r=5-0-sintheta#

#r=5-sintheta#

877 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-21T05:20:48

#r=5-4sin(pi-theta)#

#r=5-4(sinpicostheta-cospisintheta)#

#r=5-4(0*costheta-(-1)sintheta)#

#r=5-4(0+sintheta)#

#r=5-4sintheta#