Is this reaction a double displacement reaction? CH3COOH (aq) + NaHCO3 (s) → CH3COONa (aq) + CO2 (g) + H2O (l)
Half of this is a double displacement reaction.
The reaction takes place in two steps.
CH₃COOH(aq) + NaHCO₃(s) → CH₃COONa + H₂CO₃(aq)
This is a double displacement reaction because the Na trades partners with the H of CH₃COOH.
The carbonic acid formed in Step 1 decomposes into CO₂ and water.
H₂CO₃(aq) → CO₂(g) + H₂O(l)
This is a decomposition reaction, because one substance is converted into two different substances.
If you add the two equations together, the H₂CO₃ cancels out, and you get
CH₃COOH(aq) + Na₂CO₃(s) → CH₃COONa(aq) + CO₂(g) + H₂O(l)