Is y=x^2+1, y=2^(x^2) a solvable system?

Is y=x^2+1, y=2^(x^2) a solvable system?

1 Answer
May 23, 2017

Yes. It is a solvable system.

Explanation:

Making x^2=y-1 and substituting

y = 2^(y-1)

A natural solution is y=1 rArr x= 0 and after a close view also y=2 rArr x = pm 1