KClO3 → KCl + O2 How many grams of oxygen are produced in the decomposition of 5.00 grams of potassium chlorate?

1 Answer
May 1, 2018

"1.96g" O_2

Explanation:

We first need our balanced equation:
2KClO_3 rarr 2KCl + 3O_2

Now apply stoichiometry, and you result with this:

5.00"g 2KClO3" * "1mol 2KClO3"/"122.55g 2KClO3" * "3mol O2"/"2mol 2KClO3" * "16.00g O2"/"1mol O2" = "1.96g O2"