# Kevin drove his scooter 62 km in 2 h. How do you find how far he drives if he drives at the same rate of 3 hr?

Nov 21, 2016

$93 \setminus \textrm{k m}$ driven

#### Explanation:

information given

• 62 km driven in 2 h
• driving same rate in 3 h

application
If Kevin drives 62 km in 2 h, then $\frac{62 \setminus \textrm{k m}}{2 \setminus \textrm{h}} = \frac{31 \setminus \textrm{k m}}{\setminus} \textrm{h}$ is his rate.

calculation

• apply dimensional analysis with conversion factor $\frac{31 \setminus \textrm{k m}}{1 \setminus \textrm{h}}$
$3 h \setminus \times \frac{31 \setminus \textrm{k m}}{1 \setminus \textrm{h}}$
• numerator's and denominator's units cancel out
$3 \setminus \cancel{\setminus \textrm{h}} \setminus \times \frac{31 \setminus \textrm{k m}}{1 \setminus \cancel{\setminus \textrm{h}}}$
• multiply results
$\frac{3 \setminus \times 31 \setminus \textrm{k m}}{1} = \frac{93 \setminus \textrm{k m}}{1} = 93 \setminus \textrm{k m}$ driven