Question

Kids were asked if they have traveled to Euro. 68 kids indicated that they have traveled to Euro and 124 kids said that they have not traveled to Europe. If a kid is randomly selected, what is the probability of getting a a kid who went to Euro?

Answer 1

`31/48 = 64.583333% = 0.6453333`

Explanation:

The first step in solving this problem is figuring out the total amount of kids so you can figure out how many kids went to Europe over how many kids you have in total. It'll look something like `124/t`, where `t` represents the total amount of kids.

To figure out what `t` is, we find `68+124` since that gives us the sum of all the kids who were surveyed.

`68+124= 192`

Thus, `192=t`

Our expression then becomes `124/192`. Now to simplify:

`(124-:4)/(192-:4)=31/48`

Since `32` is a prime number, we can no longer simplify. You can also convert the fraction to a decimal or a percent.

`31-:48=0.64583333`
`0.64583333=64.583333%~=65%`

So, the probability (`P`) of randomly picking a kid who has travelled to Europe is `31/48 = 64.583333% = 0.6453333`