Let #f(x) = 12/(4 x + 2# how do you find f(-1)?

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Answer 1 · 2016-07-05T22:26:03

#f(-1) = -6#

All we have to do is plug in #-1# for #x#.

So:

#f(x) = 12/(4x+2)#

Plug in #-1#:

#f(-1) = 12/(4(-1)+2)#

Simplify the denominator:

#f(-1) = 12/-2#

Divide:

#f(-1) = -6#

And that's your solution.