Let #f(x)=2x-1, g(x)=3x#, and #h(x)=x^2+1#, what is #f(h(7))#?
1 Answer
Mar 3, 2018
Explanation:
#"evaluate "h(7)" then substitute result into "f(x)#
#h(color(red)(7))=(color(red)(7))^2+1=49+1=50#
#rArrf(color(red)(50))=(2xxcolor(red)(50))-1=100-1=99#
#rArrf(h(7))=99#
