Question

Let `f(x)=2x^2+2`, how do you find f(0.3)?

Answer 1

`f(x) = y =2.18`

Explanation:

`f(color(red)(x)) = 2x^2 +2" "larr` the right side shows what is done to `x`
`color(white)(x)darr`
`f(color(red)(0.3))" "larr` you are told that `x` has the value `0.3`

`f(color(red)(x)) = 2color(red)(x^2) +2`

`f(color(red)(0.3)) = 2color(red)((0.3^2)) +2`

`color(white)(xxxx) =2 xx 0.09 +2`

`color(white)(xxxx) =2.18`