# Let f(x)=3^x, what is the value of f(-1)?

Mar 10, 2018

See a solution process below:

#### Explanation:

To find the value of $f \left(- 1\right)$ we need to substitute $\textcolor{red}{- 1}$ for each occurrence of $\textcolor{red}{x}$ in $f \left(x\right)$

$f \left(\textcolor{red}{x}\right) = {3}^{\textcolor{red}{x}}$ becomes:

$f \left(\textcolor{red}{- 1}\right) = {3}^{\textcolor{red}{- 1}}$

$f \left(\textcolor{red}{- 1}\right) = \frac{1}{3} ^ \textcolor{red}{- - 1}$

$f \left(\textcolor{red}{- 1}\right) = \frac{1}{3} ^ \textcolor{red}{1}$

$f \left(\textcolor{red}{- 1}\right) = \frac{1}{3} ^ 1$

$f \left(\textcolor{red}{- 1}\right) = \frac{1}{3}$