Question

Let `f(x) = 6x^2 + 7x - 5` and g(x) = 2x - 1, how do you find f/g?

Answer 1

See a solution process below:

Explanation:

`(f/g)(x) = (6x^2 + 7x - 6)/(2x - 1)`

We can then factor the numerator:

`(f/g)(x) = ((2x - 1)(3x + 5))/(2x - 1)`

We can now cancel common terms in the numerator and denominator:

`(f/g)(x) = (color(red)(cancel(color(black)((2x - 1))))(3x + 5))/color(red)(cancel(color(black)(2x - 1)))`

`(f/g)(x) = 3x + 5`

Where:

`(2x - 1) != 0`

Or

`x != 1/2`