Let #F(x)=x^2-20# and #G(x)=14-x#, how do you find# (F/G)(7)#?

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Answer 1 · 2017-04-09T19:08:05

See the entire solution process below:

First,

#(F/G)(x) = (x^2 - 20)/(14 - x)#

To find #(F/G)(7)# we need to substitute #color(red)(7)# for each occurrence of #color(red)(x)# in #(F/G)(x)#:

#(F/G)(color(red)(x)) = (color(red)(x)^2 - 20)/(14 - color(red)(x))# becomes:

#(F/G)(color(red)(7)) = (color(red)(7)^2 - 20)/(14 - color(red)(7))#

#(F/G)(color(red)(7)) = (49 - 20)/7#

#(F/G)(color(red)(7)) = 29/7#