Let #f(x)=x^2-2x+5# and #g(x)=4/(x-1)#, how do you find #(fog)(3)#?
1 Answer
Dec 27, 2016
Explanation:
Start by finding (f￮g)(x)
To find this function, substitute
#x=4/(x-1)"That is g(x) into " f(x)#
#rArr(f￮g)(x)=(4/(x-1))^2-2(4/(x-1))+5#
#=16/(x-1)^2-8/(x-1)+5# Now substitute x = 3
#rArr(f￮g)(3)=16/(3-1)^2-8/(3-1)+5#
#=16/4-8/2+5=4-4+5=5#
