Let #f(x) = x^2+6# and #g(x) = (x+8)/x#. What is #(g*f)(-7)#?
1 Answer
Aug 30, 2017
Explanation:
#(g.f)(x)=g(x)xxf(x)#
#color(white)((g.f)(x))=(x+8)/x xx(x^2+6)#
#"to evaluate "(g.f)(-7)" substitute x = - 7 into "(g.f)(x)#
#(g.f)(color(red)(-7))=(color(red)(-7)+8)/color(red)(-7)xx((color(red)(-7))^2+6)#
#=1/(-7)xx(49+6)#
#=-1/7xx55/1#
#=-55/7#
