Let #log_(b)(A)=3# ; #log_(b)(C)=2# ; #log_(b)(D)=5# . What is the value of #log_(b)(D^(2)/((C)^(3)A))# ?

Question

(a) 1
(b) 19
(c) 0.549
(d) 4.44

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Answer 1 · 2018-01-10T12:07:58

#log_b((D^2)/((C)^3*A))=1 #

#log_b(A)=3 ; log_b(C)=2 ; log_b(D)=5#

#log_b((D^2)/((C)^3*A))=? # or

#log_b(D^2)-log_b(C^3*A)# or

#2log_b(D)-(log_b(C^3) +log_b(A))# or

#2log_b(D)-(3log_b(C) +log_b(A))# or

#2log_b(D)-3log_b(C) -log_b(A)# or

#2*5-3*2-3= 1 # [Ans]