Let #p = 4x -7#. What is equivalent to #(4x - 7)^2 + 16 = 40x - 70# in terms of #p#?

1 Answer
Johnson Z.
Jun 1, 2016

#p^2-10p+16=0#

Explanation:

To rewrite the given equation in terms of #p#, you need to simplify the equation such that the most number of "#4x-7#" appears. Thus, factor the right side.

#(4x-7)^2+16=40x-70#

#(4x-7)^2+16=10(4x-7)#

Since #p=4x-7#, replace each #4x-7# with #p#.

#p^2+16=10p#

Rewriting the equation in standard form,

#color(green)(|bar(ul(color(white)(a/a)color(black)(p^2-10p+16=0)color(white)(a/a)|)))#

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