Let #p# be a prime.Show that #S={m+nsqrt(-p) | m,n in ZZ}# is a subring of #CC#..Further,check whether or not #S# is an ideal of #CC#?

1 Answer
Feb 24, 2018

#S# is a subring but not an ideal.

Explanation:

Given:

#S = { m + nsqrt(-p) | m, n in ZZ }#

  • #S# contains the additive identity:
    #0 + 0sqrt(-p) = 0color(white)(((1/1),(1/1)))#

  • #S# is closed under addition:
    #(m_1 + n_1 sqrt(-p)) + (m_2 + n_2 sqrt(-p)) = (m_1+m_2)+(n_1+n_2) sqrt(-p)color(white)(((1/1),(1/1)))#

  • #S# is closed under additive inverse:
    #(m_1 + n_1 sqrt(-p)) + (-m_1 + -n_1 sqrt(-p)) = 0color(white)(((1/1),(1/1)))#

  • #S# is closed under multiplication:
    #(m_1 + n_1 sqrt(-p))(m_2 + n_2 sqrt(-p)) = (m_1m_2-pn_1n_2)+(m_1n_2+m_2n_1)sqrt(-p)color(white)(((1/1),(1/1)))#

So #S# is a subring of #CC#.

It is not an ideal, since it does not have the property of absorption.

For example:

#sqrt(3)(1+0sqrt(-p)) = sqrt(3) !in S#