Let #s(x) = x^2 + 2x + 3x# and #t(x) =sqrt( x+4)# how do you find #(s( t)) (6)#?
See below for explanation
We have two functions and we have to compose them in the order to find
We note that
We proceed as follows
This question asks for s(t(6)) not s(t)(6)
To solve for
let's first find s(t).
Substitute t(x) into s(x):
Simplifying this gives us:
Now, subbing 6 into the X values gives us:
Note that functions like s(t(x)) are called composite functions.