Let #theta# be an angle in quadrant II such that #sintheta = 5/6#. What are the exact values of #sec theta# and #tan theta#?

1 Answer
Jun 14, 2017

#-6/sqrt11,-5/sqrt11#

Explanation:

#• costheta=+-sqrt(1-sin^2theta)#

#color(white)(xxxxx)=-sqrt(1-(5/6)^2)larr" negative in quadrant 11"#

#color(white)(xxxxx)=-sqrt(11/36)=-sqrt11/6#

#• sectheta=1/costheta=-6/sqrt11#

#• tantheta=sintheta/costheta#

#color(white)(xxxxx)=5/6xx-6/sqrt11=-5/sqrt11#