Let #theta# be an angle in quadrant II such that #sintheta = 5/6#. What are the exact values of #sec theta# and #tan theta#?
1 Answer
Jun 14, 2017
Explanation:
#• costheta=+-sqrt(1-sin^2theta)#
#color(white)(xxxxx)=-sqrt(1-(5/6)^2)larr" negative in quadrant 11"#
#color(white)(xxxxx)=-sqrt(11/36)=-sqrt11/6#
#• sectheta=1/costheta=-6/sqrt11#
#• tantheta=sintheta/costheta#
#color(white)(xxxxx)=5/6xx-6/sqrt11=-5/sqrt11#