Let z=3(cos(15°)+isin(15°)), W= 5(cos(54°+isin(54°)). Then zw can be expressed as r(cosα°+isinβ°),where r is a real number,0≤α≤90 and 0≤β≤90.what is r+α+β?

1 Answer
Feb 20, 2018

#r=15, alpha=69^@#

Explanation:

#z=3cis15^@#
#w=5cis54^@#
#zw=3cis15^@xx5cis54^@#

#=3xx5xxcis15^@xxcis54^@#
#3xx5=15#
#cis15^@xxcis54^@=cis(15^@+54^@)#
#15^@+54^@=69^@#
#cis(15^@+54^@)=cis69^@#
#cis15^@xxcis54^@=cis69^@#
#3xx5xxcis15^@xxcis54^@=15cis69^@#
#3cis15^@xx5cis54^@=15cis69^@#

#zw=15cis69^@#

Let #rcis(alpha)=15cis69^@#
#r=15, alpha=69^@#