Question

Lim →1 x^2+3x−4/ x−1?

Answer 1

`5`

Explanation:

Note that

`x^2+3x-4=(x-1)(x+4)`
so we get

`lim_(x to 1)((x-1)(x+4))/(x-1)=lim_(x to 1)x+4=5`

Answer 2

`5`

Explanation:

`lim_(xto1)((x+4)cancel((x-1)))/cancel((x-1))`

`=lim_(xto1)(x+4)=1+4=5`