Lim xcscx x →0 how to get the answer ?

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Answer 1 · 2018-05-07T20:51:23

$lim_(xrarr0)xcscx=1$

$lim_(xrarr0)xcscx$ $=$

$lim_(xrarr0)x/sinx$ $=_(x!=0)^(x->0)$

$lim_(xrarr0)(x/x)/(sinx/x)$ $=$

$lim_(xrarr0)1/cancel(sinx/x)^1$ $=1$

or

$lim_(xrarr0)x/sinx$ $=_(DLH)^((0/0))$

$lim_(xrarr0)((x)')/((sinx)')$ $=$

$lim_(xrarr0)1/cosx$ $=1$