Log 2 (x+5)-log 2 (2x-1)=5? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer grace · Stefan V. May 21, 2018 #x=37/63# Explanation: #log_2 ((x+5)/(2x-1))=5" "# (condense it) #2^5 =(x+5)/(2x-1)" "# (#2=#base, and it stays, log becomes exponent) #32/1=(x+5)/(2x-1)" "# (cross multiply #-> 32 xx (2x-1)#) #64x-32=x+5 " "# (simplify) #63x=37 # #x=37/63# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 613 views around the world You can reuse this answer Creative Commons License