(Log 49+log 343-log 2401)÷(log16807-log 7)?

1 Answer
Jan 11, 2018

1/4

Explanation:

As,
49 = 7^2
343 = 7^3
2401 = 7^4
16807 = 7^5

Rewriting,

(log49 + log343 - log2401)/(log16807 - log7)

=> (log7^2 + log7^3 - log7^4)/(log7^5 - log7)

Using logarithmic properties,
=> (2log7 + 3log7 - 4log7)/(5log7 - log7)

=> log7/(4log7)

Hence,
the value the comes out to be 1/4

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HOPE THIS HELPS !!!!