Logx.log2x=log4x solve equatin?

1 Answer
May 5, 2018

x = 2

Explanation:

As per the question, we have :

log x . log 2x = log 4x

log x . 2x = log 4x

log 2x^2 = log 4x

2x^2 = 4x

2x^2 - 4x = 0

x^2 - 2x = 0

(x)(x - 2) = 0

:. x = 0 and 2

But x cannot be 0 as log 0 is not defined.

:. x = 2