M varies directly as the square of x. If m = 200 when x = 20, find m when x is 32?

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Answer 1 · 2017-03-10T03:05:44

The answer is #512#

#M# varies as #x^2#, so

#=> M/x^2 = k#

where #k# is a non-zero constant.

#M=200# and #x=20#, hence

#k=200/20^2 = 1/2#

Now,

#x=32#

so

#M = 1/2 xx 32^2 = 512#