Question

Magnesium is used in extraction of titanium from titanium(IV) chloride. How to calculate the mass of magnesium required to react with 1000kg of titanium (IV) chloride?

Answer 1

Well, you must a stoichiometric that represents the reaction..I make it about `250*kg`...

Explanation:

And so...

`underbrace(TiCl_4(l) + 2Mg(s))_"238.3 g" rarr underbrace(Ti(s) + 2MgCl_2(s))_"238.3 g"`

And so `"moles of titanic chloride"-=(1000*kgxx10^3*g*kg^-1)/(189.68*g*mol^-1)`

`=5272.0*mol`

And we require TWO EQUIV magnesium metal for stoichiometric reaction...

`=5272.0*molxx2xx24.31*g*mol^-1=??*g`

I am not up on the literature at the moment, but I think most titanium smelters use the Krull process, which employs magnesium as the reductant...