Question

Mass of 1.50 mol of carbon tetrafluoride?

Answer 1

Mass of 1.5 moles of `CF_4` = `132 grams`

Explanation:

Molecular Mass of Carbon Tetrafluoride (`CF_4`)

= `(1 * MW of C) + (4* MW of F)`
= `(1*12 g/(mol)) + (4*19g/(mol))`
= `88 g/(mol)`

Number of Moles = Mass/Molecular Mass

Mass = Number of Moles * Molecular Mass

Therefore, Mass of 1.5 moles of `CF_4` is

= `88 g/(mol) * 1.5 mol`

= `132 grams`