Question

Mercury vapor contains Hg atoms. What is the volume of 200. g of mercury vapor at 822 K and 0.500 atm?

Answer 1

`"134.6 L"`

Explanation:

Molar mass of mercury `"= 200.59 g/mol"`

Moles of mercury`= "200 g"/"200.59 g/mol" = "0.997 mol"`

Assuming it shows ideal behaviour, from ideal gas equation `"PV = nRT"`

`"V" = "nRT"/"P"`

`color(white)("V") = "0.997 mol × 0.0821 L atm / (mol K) × 822 K"/"0.500 atm"`

`color(white)("V") = 134.6\ "L"`