Question

Molarity of 4% (W/V) NaOH would be ??

Answer 1

Given the starting conditions....`"molarity"=1.00*mol*L^-1`

Explanation:

Given the starting conditions, we presume that a `4*g` mass of sodium hydroxide is dissolved in a `100*mL` volume of water....and such a dissolution would involve MINIMAL change to the volume....

And the given definition of `"molarity"="moles of solute (mol)"/"volume of solution (L)"`...and thus units of `mol*L^-1`.

And so we take the quotient...

`((4*g)/(40.0*g*mol^-1))/(100*mLxx10^-3*L*mL^-1)=1.00*mol*L^-1`