Monotonic Function?

Is #tan^-1x# a monotonically increasing function for all #x# belongs to #R# ?

2 Answers
May 6, 2017

Yes. See the Explanation.

Explanation:

Let #f(x)=tan^-1x, x in RR.#

#:. f'(x)=1/(1+x^2).#

Now, #AA x in RR, x^2 ge 0 rArr 1+x^2 ge 1.#

# rArr f'(x)=1/(1+x^2) gt 0, aa x in RR.#

We coclude that, #f(x)=tan^-1x, x in RR" is "uarr.#

May 6, 2017

Yes.

Explanation:

Yes it is, because deriving it

#d/(dx) arctan(x) = 1/(1+x^2) > 0# so

#f(x) = int_a^x (d xi)/(1+ xi^2)# is a monotonically increasing function from #a# to #oo#