Mrs. Phillips has 10 identical cans without labels. She knows that she had 1 can of peas, 5 cans of corn, 1 can of carrots, and 3 cans of beets. She opens one can. What is the probability it is carrots?Corn or beets?

Feb 27, 2017

$P \left(\text{carrots}\right) = \frac{1}{10}$

$P \left(\text{corn or beets}\right) = \frac{8}{10} = \frac{4}{5}$

Explanation:

The formula to determine the probability of an event occurring is:

$\text{the number of desirable outcomes"/"total number of possible outcomes}$

Only 1 of the 10 identical cans are carrots.

$P \left(\text{carrots}\right) = \frac{1}{10}$

There are 8 cans which have corn or beets.

$P \left(\text{corn or beets}\right) = \frac{8}{10} = \frac{4}{5}$

Notice that, when options are available, "OR" increases the probability. In this case, if the lady is equally happy to open a can of beet or corn, there are 8 tins which will meet this requriement.