N 2 ( g ) + 3 H 2 ( g ) ⟶ 2 N H 3 ( g ) In a certain reaction, 5.0 moles of hydrogen is reacted with excess nitrogen. To determine how many moles of ammonia are produced, what conversion factor should be used?

Please help! I dont understand this unit at all and need someone to explain!

1 Answer
Apr 25, 2018

Here H_2 will act as the Limiting reagent because the N_2 is take in excess. See below :-

Explanation:

N_2 + 3H_2 ⟶ 2NH_3

On dividing by 3 , this equation can be rewritten as :-

1/3N_2 + H_2 ⟶ 2/3NH_3

This equation explains that for 1 mole of H_2 the number of moles of NH_3 formed will be 2/3. (when N_2 is in excess)

So for 5 moles of H_2 the number of moles of NH_3 formed =2/3 xx 5 =10/3moles

Thus the number of moles of Ammonia formed =10/3