Question

`((n+3)!)/((n-3)!)=?`

Answer 1

`((n+3)!)/((n-3)!)`

`=>((n+3)(n+2)(n+1)(n)(n-1)(n-2)cancel((n-3)!))/(cancel((n-3)!)`

`=>(n+3)(n+2)(n+1)(n)(n-1)(n-2)`