# Need help solving. I'm stuck at this part, do I change it to log form next?

Nov 27, 2017

$x = \frac{7}{10}$

#### Explanation:

$\left(\frac{1}{5} ^ 2\right)$ is the same as saying $\left({5}^{-} 2\right)$ , so you can then write the equation as:

${\left({5}^{-} 2\right)}^{2 - 5 x} = {5}^{3}$

${5}^{- 4 + 10 x} = {5}^{3}$

$\log {5}^{- 4 + 10 x} = \log {5}^{3}$

$- 4 + 10 x = 3$

$10 x = 7$

$x = \frac{7}{10}$