Question

`NiCl_3` is a strong electrolyte. How do you determine the concentration of each of the individual ions in a 0.400 M `NiCl_3` solution?

Answer 1

I think you mean `NiCl_2`.

Explanation:

In aqueous solution, nickel chloride gives a beautiful green solution, which we would represent as `[Ni(OH_2)_6]^(2+)` or simply as `Ni^(2+)(aq)`. Two (aquated) chloride counterions, `Cl^(-)(aq)`, are along for the ride.

The concentration of the hexaqua complex is (clearly) `0.400*mol*L^-1`. The concentration of the chloride counterions is `0.800*mol*L^-1`.