Question

Nitric and sodium hydroxide = sodium nitrate plus water what is the balanced equation?

Answer 1

`HNO_3 + NaOH = NaNO_3 + H_2O`

Explanation:

The two reactants react in a one to one ratio. One molecule of Nitric acid (`HNO_3`) is neutralized by one molecule of sodium hydroxide (`NaOH`)

Answer 2

The balanced equation is `"HNO"\_3+"NaOH"->"NaNO"_3+"H"_2"O"`.

Explanation:

First, get each part into "chemistry form".

Nitric acid is an acid, so there will be one or more `"H"^+`'s in front.

Since the suffix of "nitric" is "-ic", we know that the polyatomic in the acid is nitrate (and not nitrite) which is `"NO"_3^-`. So, nitric acid is `"HNO"_3`.

Next is sodium hydroxide. Sodium is `"Na"^+` and hydroxide is `"OH"^-`, so we can just put them together in an ionic bond as `"NaOH"`.

Next is sodium nitrate. Again, sodium is `"Na"^+` and nitrate is `"NO"_3^-`, so sodium nitrate is `"NaNO"_3`.

Last is water, which we know is `"H"_2"O"`.

Now, write out the chemical formula but leave blanks for any numbers we might have to write:

`"__" "HNO"\_3+"__""NaOH"->"__""NaNO"_3+"__""H"_2"O"`

Now, count the number of each atom on each side to see if we have to change anything.

#color(white){color(black)( ("Element", "Amount on left side", "Amount on right side"), ("H",2,2), ("N",1,1), ("O",4,4), ("Na",1,1)):}#

Since the elements on the left side are in the same amounts as the elements on the right side, the equation is already balanced, so we don't need to add any numbers. This means that the final equation is:

`"HNO"\_3+"NaOH"->"NaNO"_3+"H"_2"O"`

Hope this helped!