Question

Number of HCL molecules present in 10ml of 0.1N HCL solution is?

Answer 1

Recall,

`"N" = (1"g")/"L"`

Note: this is seen less often outside of laboratories.

Hence, there are,

`10"mL" * "L"/(10^3"mL") * (0.1"g")/"L" * ("mol")/(36.5"g") * (6.02*10^23"molecules")/"mol" approx 1.7*10^19"molecules"`

of hydrochloric acid present in that small volume of `0.1"N"` solution.