# Number of solutions of sin^2θ+3cosθ=3 in [-π,π] ?

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Nghi N.
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Jun 23, 2018

#### Answer:

One answer: t = 0

#### Explanation:

Replace in the equation

Sine a + b + c = 0, use shortcut. The 2 real roots are:

cos x = 1 and

cos x = 1.

Unit circle gives --> t = 0, and

Inside the interval

t = 0

Check

t = 0 --> sin^2 t = 0 --> 3cos t = 3

sin^2 t + 3cos t = 0 + 3 = 3. Proved.

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