Question

OH | CH2 | C=O | CH-CH2-Br | C=O | CH3 What is the IUPAC nomenclature of this compound ?

Answer 1

The IUPAC name is 3-(bromomethyl)-1-hydroxypentane-2,4-dione.

Explanation:

I think this is the structure you are trying to draw.

Here's how you generate the IUPAC name.

Step 1. Find the longest continuous chain of carbon atoms

The longest continuous chain contains five carbon atoms, so the parent hydrocarbon is pentane.

Step2. Identify the functional group of highest priority

The molecule contains `"OH, Br"`, and `"C=O"` groups.

The ketone groups have the highest priority, so this is a pentanedione.

We must name the other groups as substituents.

Step 3. Number the carbon atoms in the chain

We number from the end closest to a substituent (the `"OH"` group).

The name becomes pentane-2,4-dione.

Step 4. Name and locate the substituents

The `"OH"` group is on `"C1"`, so it is 1-hydroxy.

The `"BrCH"_2` group is on `"C3"`, so it is a 3-(bromomethyl) group. We enclose the name in parentheses to make it clear that "bromo" goes with "methyl."

Step 5. Attach the names of the groups to the parent name in alphabetical order.

The IUPAC name is 3-(bromomethyl)-1-hydroxypentane-2,4-dione.