OH | CH2 | C=O | CH-CH2-Br | C=O | CH3 What is the IUPAC nomenclature of this compound ?

1 Answer
Feb 15, 2018

The IUPAC name is 3-(bromomethyl)-1-hydroxypentane-2,4-dione.

Explanation:

I think this is the structure you are trying to draw.

StructureStructure

Here's how you generate the IUPAC name.

Step 1. Find the longest continuous chain of carbon atoms

The longest continuous chain contains five carbon atoms, so the parent hydrocarbon is pentane.

Step2. Identify the functional group of highest priority

The molecule contains OH, Br, and C=O groups.

The ketone groups have the highest priority, so this is a pentanedione.

We must name the other groups as substituents.

Step 3. Number the carbon atoms in the chain

We number from the end closest to a substituent (the OH group).

The name becomes pentane-2,4-dione.

Step 4. Name and locate the substituents

The OH group is on C1, so it is 1-hydroxy.

The BrCH2 group is on C3, so it is a 3-(bromomethyl) group. We enclose the name in parentheses to make it clear that "bromo" goes with "methyl."

Step 5. Attach the names of the groups to the parent name in alphabetical order.

The IUPAC name is 3-(bromomethyl)-1-hydroxypentane-2,4-dione.