# On the figure given show that #bar(OC)# is #sqrt(2)#?

##### 1 Answer

Sep 14, 2016

WOW...I finally got it...although it seems too easy...and probably it is not the way you wanted it!

#### Explanation:

I considered the two small circles as equal and having radius *unity* in distance

According to this, the distance

Now, I applied Pythagoras to the triangle

or:

so:

Does it make sense...?