On what points does f(x)=(lnx)^2 continous?

1 Answer
VNVDVI
Apr 9, 2018

#(0, oo)#

Explanation:

Recall that for #g(x)=lnx, x>0,# as the logarithm does not exist for zero or negative numbers. The domain of the logarithmic function is #(0, oo)#

For #f(x)=(lnx)^2#, the aforementioned domain does not change because of squaring the entire function; we still cannot plug in zero or negative values for #x.#

So, the function is continuous on #(0, oo)#

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