# One canned juice drink is 25% orange juice; another is 5% orange juice. How many liters of each should be mixed together in order to get 20L that is 6% orange juice?

$1$ litre of 25% orange juice mixed with $19$ litre of 5% orange juice to get $20$ litre of 6% orange juice.
Let $x$ litre of 25% orange juice mixed with $\left(20 - x\right)$ litre of 5% orange juice to get $20$ litre of 6% orange juice.
So by condition given , $x \cdot 0.25 + \left(20 - x\right) \cdot 0.05 = 20 \cdot 0.06 \mathmr{and} 0.25 x - 0.05 x = 1.2 - 1 \mathmr{and} 0.2 x = 0.2 \mathmr{and} x = 1 \therefore \left(20 - x\right) = 20 - 1 = 19$
Therefore $1$ litre of 25% orange juice mixed with $19$ litre of 5% orange juice to get $20$ litre of 6% orange juice.[Ans]