# One integer is 3 more than another. Their product is 70. How do you find the integers?

##### 1 Answer

Apr 4, 2018

#### Answer:

#### Explanation:

Let the integers be

Conditions given are

#x = y + 3#

#xy = 70#

First equation can be written as

#x = 70/x + 3#

#x - 70/x = 3#

#(x^2 - 70)/x = 3#

#x^2 - 70 = 3x#

#x^2 - 3x - 70 = 0#

#x^2 + 10x - 7x - 70 = 0#

#x(x + 10) - 7(x + 10) = 0#

#(x -7)(x + 10) = 0#

#x = -7# or#x = 10#

If

Value of

If

Value of

Therefore, two sets of integers are possible: