# One of the most commonly used compounds in the chlorination of swimming pools is sodium hypochlorite, NaClO. Once dissolved, an equilibrium is established between ClO^- and its conjugate acid. What is the equation of this reaction?

Aug 8, 2018

$C l {O}^{-} + {H}_{2} O \left(l\right) r i g h t \le f t h a r p \infty n s H O C l \left(a q\right) + H {O}^{-}$

#### Explanation:

As always the conjugate acid is the original species PLUS a PROTON.

For..

$C l {O}^{-} + {H}_{2} O \left(l\right) r i g h t \le f t h a r p \infty n s H O C l \left(a q\right) + H {O}^{-}$

${K}_{\text{eq}} = \frac{\left[H {O}^{-}\right] \left[H O C l \left(a q\right)\right]}{\left[C l {O}^{-}\right]} = {10}^{- 6.47} = 3.38 \times {10}^{-} 7$