# One of the sides of an equilateral triangle is 61. What is the height of the triangle?

## geometry

Feb 17, 2018

given, $\text{side = 61 units}$

"area of the triangle" = color(magenta)(sqrt3/4 (side)^2
$A = \frac{\sqrt{3}}{4} \cdot 61 \cdot 61$

also, "area of the triangle" = color(magenta)(1/2 (base)(height)
$\frac{\sqrt{3}}{4} \cdot 61 \cdot 61 = \frac{1}{2} \cdot 61 \cdot \left(h e i g h t\right)$
$\frac{\sqrt{3}}{2} \cdot 61 = \left(h e i g h t\right)$

$\text{height} = \frac{61 \sqrt{3}}{4} u n i t s$

-Sahar :)