One of two identical balloons contained carbon dioxide (CO2, 44 g mol−1) and the other contained hydrogen (H2, 2.0 g mol−1). If it took 24 hours for all of the H2 to escape from its balloon, how long did it take for all of the CO2 to escape?

1 Answer
Apr 21, 2017

Answer:

#112.569978 hours# which rounds to #110 hours# due to significant figures.

Explanation:

Use Graham's Law:
#r_1/r_2 = sqrtM_2/sqrtM_1 = t_2/t_1#
Note: #r# is the rate of effusion, #M# is the molar mass of the gas, and #t# is the time the gas took to effuse. Also, know that this formula only works if both gasses are at the same temperature.

Since molar mass and time is given, we will use the second half of the formula.

#sqrt("molar mass" CO_2)/sqrt("molar mass"H_2) = (time CO_2)/(time H_2)#

#sqrt(44g*mol^(-1) CO_2)/sqrt(2.0g*mol^(-1)H_2) = (time CO_2)/(24 hours H_2)#

#((24 hours H_2)*sqrt(44g*mol^(-1) CO_2))/sqrt(2.0g*mol^(-1)H_2) = time CO_2#

#time CO_2 = 112.569978 hours#

Since there are only 2 significant figures the answer would be #110 hours#